12x+1=3[4x+1]-2

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Solution for 12x+1=3[4x+1]-2 equation:


Simplifying
12x + 1 = 3[4x + 1] + -2

Reorder the terms:
1 + 12x = 3[4x + 1] + -2

Reorder the terms:
1 + 12x = 3[1 + 4x] + -2
1 + 12x = [1 * 3 + 4x * 3] + -2
1 + 12x = [3 + 12x] + -2

Reorder the terms:
1 + 12x = 3 + -2 + 12x

Combine like terms: 3 + -2 = 1
1 + 12x = 1 + 12x

Add '-1' to each side of the equation.
1 + -1 + 12x = 1 + -1 + 12x

Combine like terms: 1 + -1 = 0
0 + 12x = 1 + -1 + 12x
12x = 1 + -1 + 12x

Combine like terms: 1 + -1 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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